How Do I Check If A Checkbox Is Checked Or Unchecked? (In QTreeWidget)
I have written the code below: from PyQt4 import QtCore, QtGui import sys class window(QtGui.QMainWindow): def __init__(self, parent=None): super(window, self).__init_
Solution 1:
Using itemClicked
signal:
class window(QtGui.QMainWindow):
def __init__(self, parent=None):
super(window, self).__init__(parent)
self.TreeWidget = QtGui.QTreeWidget()
self.TreeWidget.setColumnCount(1)
# self.item1/2/3 = .... save reference to the items
# to access them in the callback (check_status)
item1 = self.item1 = QtGui.QTreeWidgetItem(["Item 1"])
item1.setCheckState(0, QtCore.Qt.Checked)
item2 = self.item2 = QtGui.QTreeWidgetItem(["Item 2"])
item2.setCheckState(0, QtCore.Qt.Unchecked)
item3 = self.item3 = QtGui.QTreeWidgetItem(["Item 3"])
item3.setCheckState(0, QtCore.Qt.Unchecked)
self.TreeWidget.addTopLevelItem(item1)
self.TreeWidget.addTopLevelItem(item2)
self.TreeWidget.addTopLevelItem(item3)
self.setCentralWidget(self.TreeWidget)
# connect the itemClicked signal to the callback check_status.
self.TreeWidget.itemClicked.connect(self.check_status)
def check_status(self):
if self.item1.checkState(0) == QtCore.Qt.Checked:
print('item 1 is checked')
if self.item2.checkState(0) == QtCore.Qt.Checked:
print('item 2 is checked')
if self.item3.checkState(0) == QtCore.Qt.Checked:
print('item 3 is checked')
Solution 2:
A checkbox is a kind of value in the field. It is different from the text, but still the value.
The checkbox can be triggered with a mouse event or with a keyboard event (space bar). Therefore, the simplest way to recognize such an event is to subclass QTreeWidgetItem
and store the last checkbox state in it as a variable of type QtCore.Qt.CheckState
.
Please, consider the following piece of code:
from __future__ import annotations
from PyQt5.QtWidgets import *
from PyQt5.QtCore import *
from PyQt5.QtGui import *
import sys, typing
class MyTree(QTreeWidget):
class MyItem(QTreeWidgetItem):
def __init__(self, parent):
super().__init__(parent)
# Assuming, that an element has only one checkbox
#
self.storedCheckedState: QtCore.Qt.CheckState = self.checkState(0)
# Otherwise, we need more stored variables here
def setCheckState(self, column: int, state: QtCore.Qt.CheckState) -> None:
# The chekbox in the first column:
if column == 0:
self.storedCheckedState = state
return super().setCheckState(column, state)
def __init__(self, parent: typing.Optional[QWidget]=None) -> None:
super().__init__(parent=parent)
self.setColumnCount(4)
header = MyTree.headerItem(self)
header.setText(1, 'A')
header.setText(2, 'B')
header.setText(3, 'C')
header.setText(4, 'D')
def changed(self, item:MyTree.MyItem, column:int) -> None:
if column == 0:
if item.storedCheckedState != item.checkState(0):
print("Item checked!")
item.storedCheckedState = item.checkState(0)
else:
print("Item edited, but not checked!")
else:
print("Some field edited...")
def loadData(self, data:typing.Any) -> None:
# stop events propagation
try:
self.disconnect()
except:
pass
# Load the data there...
# In this particular case,
# the tree will be simply generated:
#
# [ ] Parent 1
# [ ] Child 1
# [ ] Child 2
# [ ] Child 3
# ...
for i in range(3):
# parent = QTreeWidgetItem(tree)
parent = MyTree.MyItem(self)
parent.setText(0, "Parent {}".format(i))
parent.setFlags(parent.flags() | Qt.ItemIsTristate | Qt.ItemIsUserCheckable | Qt.TextEditable | Qt.ItemIsEditable)
for x in range(5):
child = MyTree.MyItem(parent)
child.setFlags(child.flags() | Qt.ItemIsUserCheckable | Qt.TextEditable | Qt.ItemIsEditable)
child.setText(0, "Child {}".format(x))
child.setCheckState(0, Qt.Unchecked)
# restore events propagation
self.itemChanged.connect(self.changed)
def main():
app = QApplication (sys.argv)
tree = MyTree()
tree.loadData("ANY DATA")
tree.show()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
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