Open Json File Link Through A Code
I'm creating an addon and I'm modifying some functions that come within a py file. What I intend to do is the following, I have this code: This code gives access to a lib.json fil
Solution 1:
Given that your link holds valid json - which is not the case with the content you posted - you could use requests.
If the content at dropbox looked liked this:
{"tv":
{"epg": "tv",
"streams":
[{"url": "http://topchantv.net:3456/live/Stalker/Stalker/838.m3u8",
"name": "IPTV",
"resolve": False,
"visible": True}],
"name": "tv",
"thumb": "thumb_tv.png"
}
}
Then fetching the content would be like this
import requests
url = 'https://www.dropbox.com/s/sj1246qtiodm6qd/lib.json?dl=1'
r = requests.get(url)
json_object = r.json()
So if you needed it inside a function, I guess you'd input the url and return the json like so:
def channellist(url):
r = requests.get(url)
json_object = r.json()
return json_object
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